-5t^2=-1.8

Solution for -5t^2=-1.8 equation:

-5t^2=-1.8

We move all terms to the left:

-5t^2-(-1.8)=0

We add all the numbers together, and all the variables

-5t^2+1.8=0

a = -5; b = 0; c = +1.8;
Δ = b2-4ac
Δ = 02-4·(-5)·1.8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6}{2*-5}=\frac{-6}{-10}
=3/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6}{2*-5}=\frac{6}{-10}
=-3/5
$